Seudónimo Seudónimo
  • 02-05-2016
  • History
contestada

Solve ax2 + bx +c = 0 when a=5, b = -23 and c = 12 to find the zeros (x intercepts)

Respuesta :

konrad509
konrad509 konrad509
  • 02-05-2016
[tex]5x^2-23x+12=0\\ 5x^2-20x-3x+12=0\\ 5x(x-4)-3(x-4)=0\\ (5x-3)(x-4)=0\\ x=\dfrac{3}{5} \vee x=4 [/tex]
Answer Link

Otras preguntas

Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D. Side B C is 3. 8 units. Side A p
Why did the united states help overthrow governments in guatemala and iran?.
please help me with this question
work out the value of x
The angle of ABC is how many degrees​
PLS HELP ITS BEING TIMED Which option is an example of a renewable resource? جام A. Electricity from solar panels on a house B. Heat and energy made from burni
A bookstore bought a case of 10 books at a wholesale price of $84. The bookstore will sell the books at a 25 percent markup, and each book will be sold for the
b2+16 ? #Evaluate the expression when b=5.
Meena mowed 9 lawns in 18 hours. What was her rate of mowing in lawns per hour?
A square has a diagonal of length 12. Find the length of each side.