The concentration of [H30+] in the solution when the pH of the solution is [tex]1.32*10^8\ m.[/tex]
Since The pH of a solution is 7.880
So here
pH = -log{H+}
{H+} = [tex]10^-PH[/tex]
[H30+] [tex]= 10^{-7.88}[/tex]
[tex]= 1.3182*10^-8\ mol\\\\= 1.32*10^-8\ m[/tex]
hence, The concentration of [H30+] in the solution is [tex]1.32*10^8\ m.[/tex]
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