parkevylin parkevylin

03-11-2020
Physics

contestada

a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per sec to 8 metre per second find the magnitude of the applied force

Respuesta :

neemoneemo93 neemoneemo93

03-11-2020

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N

Answer Link

Otras preguntas

An aircraft has a liftoff speed of 33 m/s. what minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240m?

What is the value of 1-18+25 if you subtract then add? If you add then subtract?Why is order of operations necessary?

what is 69/25 as a terminating decimal

how is a knoll formed

Find the original cost of a rocker selling for $159.95 at 20% off.

An aircraft has a liftoff speed of 33 m/s. what minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240m?

Which best describes Germany’s standard invasion strategy at the beginning of World War II?a. Attack with a combination of speed and overwhelming forceb. Intimi

how many kilograms is in 12,321grams

What Was Jackson’s perspective on the McCulloch v. Maryland Supreme Court Case

what are some fun facts on animal and plant cells.