Answer:
Ā Pā= 141.15 kPa Ā
Explanation:
Given that
Volume ,V= 3 L
V= 0.003 mĀ³
Initial temperature ,Tā = 273 K
Initial pressure ,Pā = 105 kPa
Final temperature ,Tā = 367 K
Given that volume of the cylinder is constant .
Lets take final pressure = Pā
We know that for constant volume process
[tex]\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\P_2=P_1\times \dfrac{T_2}{T_1}\\P_2=105\times \dfrac{367}{273}\ kPa\\\\P_2=141.15\ kPa[/tex]
Therefore the final pressure = 141.15 kPa
Pā= 141.15 kPa
