Answer:
Mass = 889.8 g
Explanation:
Given data:
Mass of Mg(NO₃)₂ required = ?
Volume of solution = 1.5 L
Molarity of solution = 4 M
Solution:
we will calculate the number of moles from molarity formula then we will calculate the mass from number of moles.
Formula:
Molarity = number of moles / Volume in L
4 M = number of moles / 1.5 L
Number of moles = 4 M× 1.5 L
Number of moles = 6 mol/L × L
Number of moles = 6 mol
Mass of Mg(NO₃)₂:
Mass= number of moles ×molar mass
Mass = 6 mol × 148.3 g/mol
Mass = 889.8 g
