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Engine 1 has an efficiency of 0.18 and requires 5500 J ofinput heat to perform a certain amount of work. Engine 2 hasan efficiency of 0.26 and performs the same amount of work. How much input heat does the second engine require?

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okpalawalter8

Answer:

The input energy to  engine 2  is [tex]E_2 = 3807.7\ J[/tex]

Explanation:

From the question we are told that

     The efficiency of engine one is  [tex]\eta_1 = 0.18[/tex]

     The input energy required is [tex]E = 5500 \ J[/tex]

       The efficiency of engine 2 is [tex]\eta_2 = 0.26[/tex]

       

Generally the workdone by the engine 1  is mathematically represented as

       [tex]W_1 = E * \eta_1[/tex]

=>     [tex]W_1 = 5500 * 0.18[/tex]

=>     [tex]W _ 1= 990 \ J[/tex]

Generally the workdone by engine 2  is mathematically represented as  

        [tex]W _2= E_1 * \eta_2[/tex]

=>     [tex]W _2 = E_1 * 0.26[/tex]

=>     [tex]W_2 =0.26E_1[/tex]

From the question we are told that [tex]W_1 = W_2[/tex]

So  

       [tex]990 =W_2 =0.26E_1[/tex]

=>     [tex]E_2 = 3807.7\ J[/tex]

         

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