Respuesta :

drpelezo

Answer:

293 grams Fe₂S₃(s)

Explanation:

16Fe(s)  +     3S₈(s)     =>     8Fe₂S₃(s)

Excess  |   1.25 mole    |         ? grams

moles Fe₂S₈ produced = 8/3(1.25) mole Fe₂S₃(s) Yield = 3.33 mole  Fe₂S₃(s)

∴ grams of  Fe₂S₈ = 3.33 mole x 88 g/mole = 293 grams Fe₂S₃(s)