Question 1 (Essay Worth 10 points)
(07.01, 07.02 MC)

An expression is shown below:

4ck2 + 10k2 βˆ’ 16ck βˆ’ 40k

Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)

Part B: Factor the entire expression completely. Show the steps of your work. (6 points)

Respuesta :

MIK0

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The answer is: 2(k2βˆ’4k)(2c+5)

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Step:

* Consider 2ck2+5k2βˆ’8ckβˆ’20k. Do the grouping 2ck2+5k2βˆ’8ckβˆ’20k=(2ck2+5k2) +(βˆ’8ckβˆ’20k), and factor out k2 in the first and βˆ’4k in the second group.

* Factor out the common term 2c+5 by using the distributive property.

* Rewrite the complete factored expression.

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Answer:

2(k2βˆ’4k)(2c+5)

Step-by-step explanation: