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Determine the percentage by mass of each element in the following compounds. (Round your answers to one decimal place.)(a)milk of magnesia, Mg(OH)2Mg:____%O:______%H:______%(b)lye, NaOHNa:____%O:_____%H:_____%

Respuesta :

Firstly we will calculate the mass of the molecule by adding the together the atomic mass of each element:

[tex]\begin{gathered} Mg:24.31g \\ O:16.00g \\ H:1.00g \\ _mMg(OH)_2=24.31+(16.00\times2)+(1.01\times2) \\ _mMg(OH)_2=58.33gmol^{-1} \\ \\ \\ Na:22.99g \\ O:16.00g \\ H:1.01g \\ _mNaOH=22.99+16.00+1.01 \\ _mNaOH=40gmol^{-1} \end{gathered}[/tex]

Now we will determine the percentage mass of each of element:

[tex][/tex]

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